2. Solved Papers
  3. NEET

NEET AIPMT SOLVED PAPER SCREENING 2006

  • question_answer
                    The time of reverberation of a room A is one second. What will be the time (in seconds) of reverberation of a   room, having all the dimensions double of those of room A?                                                      

    A)                  2                            

    B)                  4                            

    C)                  \[\frac{1}{2}\]                 

    D)                  1

    Correct Answer: A

    Solution :

                    Sabine's formula for reverberation time is                 \[T=\frac{0.16\,V}{\Sigma as}\]                 where V is volume of hall in \[{{m}^{3}}\].                 \[\Sigma as={{a}_{1}}{{s}_{1}}+{{a}_{2}}{{s}_{2}}+......=\]                 total absorption of the hall (room)                 Here, \[{{s}_{1}},{{s}_{2}},{{s}_{3}}....\]are surface areas of the absorbers and \[{{a}_{1}},{{a}_{2}},{{a}_{3}}\]....... are their respective absorption coefficients                 \[\therefore \frac{T'}{T}=\frac{V'}{s'}\times \frac{s}{V}\]                 \[=\frac{{{(2)}^{3}}}{{{(2)}^{2}}}=\frac{8}{4}=2\]                 Hence,  \[T'=2T=2\times 1=2s\]


You need to login to perform this action.
You will be redirected in 3 sec spinner