A) 73
B) 74
C) 75
D) 72
Correct Answer: D
Solution :
Let radius of \[_{4}^{9}Be\] nucleus be r. Then radius of germanium (Ge) nucleus will be 2r. Radius of a nucleus is given by \[R={{R}_{0}}\,\,{{A}^{1/3}}\] \[\therefore \frac{{{R}_{1}}}{{{R}_{2}}}={{\left( \frac{{{A}_{1}}}{{{A}_{2}}} \right)}^{1/3}}\] \[\Rightarrow \frac{r}{2r}={{\left( \frac{9}{{{A}_{2}}} \right)}^{13}}(\because \,{{A}_{1}}=9)\] \[\Rightarrow {{\left( \frac{1}{2} \right)}^{3}}=\frac{9}{{{A}_{2}}}\] Hence, \[{{A}_{2}}=9\times {{(2)}^{3}}\] \[=9\times 8\] = 72 Thus, in germanium (Ge) nucleus number of nucleus is 72.
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