A) 200 J
B) 100 J
C) zero
D) 1000 J
Correct Answer: B
Solution :
Net work done in sliding a body up to a height h on inclined plane = Work done against gravitational force + Work done against frictional force \[\Rightarrow \,\,\,\,\,\,W={{W}_{g}}\,+{{W}_{f}}\] (1) but W = 300 J \[{{W}_{g}}\,=mgh\,=2\times 10\times 10\,=200\,J\] putting in Eq. (i), we get \[300=200+{{W}_{f}}\] \[\Rightarrow \,\,\,\,\,\,\,\,\,{{W}_{f}}\,=3000\,-200\,=100\,J\]
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