NEET AIPMT SOLVED PAPER SCREENING 2006

  • question_answer
                    One turn of the helix in a B-form DNA is approximately:                                                               

    A)                  20 nm           

    B)                  0.34 nm              

    C)                  3.4 nm   

    D)                  2 nm

    Correct Answer: C

    Solution :

                    B-DNA is helical structure with \[20\overset{\text{o}}{\mathop{\text{A}}}\,\] diameter and the distance between the two base pairs is \[3.4\overset{\text{o}}{\mathop{\text{A}}}\,\] and there are 10 base pairs in each turn or pitch (one round). Hence, one turn of the helix is approximately \[34\overset{\text{o}}{\mathop{\text{A}}}\,\]  or 3.4 nm \[(10\overset{\text{o}}{\mathop{\text{A}}}\,\,=1.0\,nm)\]


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