A) phosphorus pentachloride
B) hypochlorous acid
C) chlorine
D) hydrochloric acid
Correct Answer: A
Solution :
The \[\text{ OH}\] group of alcohol or the \[\text{COOH}\] group of a carboxylic acid is replaced by \[\text{Cl}\] using phosphorus penta chloride \[\left( \text{i}.\text{e}.,\text{ PC}{{\text{l}}_{5}} \right)\]\[\underset{Alcohol}{\mathop{ROH}}\,+PC{{l}_{5}}\xrightarrow{{}}RCl+POC{{l}_{3}}+HCl\] \[\underset{Acid}{\mathop{RCOOH}}\,+PC{{l}_{5}}\xrightarrow{{}}RCOCl+POC{{l}_{3}}+HCl\]
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