NEET AIPMT SOLVED PAPER SCREENING 2004

  • question_answer
    A male human is heterozygous for autosomalgenes A and B and is also hemizygous for haemophilic gene h. what proportion of his sperms will be abh?                                                                                    

    A) \[\frac{1}{8}\]                                   

    B) \[\frac{1}{32}\]                                

    C) \[\frac{1}{16}\]                                

    D)  \[\frac{1}{4}\]

    Correct Answer: A

    Solution :

    The genotype of human male in question must be Aa Bb \[{{X}^{h}}Y\]. Hence \[2\times 2\times 2=8\] types of gametes would be formed. AB \[{{X}^{h}},\] ABY, aB \[{{X}^{h}}\]. aBY, Ab \[{{X}^{h}},\] AbY, ab \[{{X}^{h}}\] abY. Hence, 1/8 proportion of his sperms-would be abh.


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