NEET AIPMT SOLVED PAPER SCREENING 2004

  • question_answer
    A solid compound 'X' on heating gives \[C{{O}_{2}}\]gas and a residue. The residue mixed with water forms on passing an excess of \[C{{O}_{2}}\]through ?Y? in water, a clear solution, 'Z' is obtained. On boiling 'Z' compound 'X' is reformed. The compound 'X' is:   

    A)                                                                                                 \[\text{Ca}{{\left( \text{HC}{{\text{O}}_{\text{3}}} \right)}_{\text{2}}}\]

    B)                \[\text{CaC}{{\text{O}}_{\text{3}}}\]

    C) \[\text{N}{{\text{a}}_{\text{2}}}\text{C}{{\text{O}}_{\text{3}}}\]                    

    D) \[{{\text{K}}_{2}}C{{O}_{3}}\]

    Correct Answer: B

    Solution :

      Compound 'X' is \[~\text{CaC}{{\text{O}}_{\text{3}}}.\] \[\underset{'X'}{\mathop{CaC{{O}_{3}}}}\,\xrightarrow{\Delta }\underset{\operatorname{Re}sidue}{\mathop{CaO}}\,+C{{O}_{2}}\uparrow \] \[\underset{\text{Residue}}{\mathop{CaO}}\,+{{H}_{2}}O\xrightarrow{{}}Ca{{\underset{'Y'}{\mathop{(OH)}}\,}_{2}}\] \[Ca\underset{'Y'}{\mathop{{{(OH)}_{2}}}}\,+\underset{Excess}{\mathop{C{{O}_{2}}}}\,+{{H}_{2}}O\xrightarrow{{}}Ca{{(HC{{O}_{3}})}_{2}}\] \[Ca{{(HC{{O}_{3}})}_{2}}\xrightarrow{\Delta }\underset{'X'}{\mathop{CaC{{O}_{3}}}}\,+{{H}_{2}}O+C{{O}_{2}}\uparrow \]


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