A) 414 s
B) 552 s
C) 690 s
D) 276 s
Correct Answer: C
Solution :
Enzyme-catalysed reactions follow first order kinetics. \[\because \]Fall of concentration from 1.28 mg \[{{\text{L}}^{-1}}\]to \[\text{0}\text{.04}\,\text{mg}\,{{\text{L}}^{-1}}\] involves five half-lives. \[1.28\,\xrightarrow[{}]{{{T}_{1/2}}}0.64\xrightarrow[{}]{{{t}_{1/2}}}0.32\xrightarrow[{}]{{{t}_{1/2}}}0.16\] \[\xrightarrow[{}]{{{t}_{1/2}}}0.08\xrightarrow[{}]{{{t}_{1/2}}}0.04\] \[\therefore \]Time required \[=5\times {{t}_{1/2}}\] \[=5\times 138\,s\] = 690 s.You need to login to perform this action.
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