NEET AIPMT SOLVED PAPER MAINS 2011

  • question_answer
    A small mass attached to a string rotates on frictionless table top as shown. If the tension is the string is increased by pulling the string causing the radius of the circular motion to decrease by a factor of 2, the kinetic energy of the mass will                        

    A)  remain constant

    B)  increase by a factor of 2

    C)  increase by a factor of 4

    D)  decrease by a factor of 2

    Correct Answer: C

    Solution :

    From the law of conservation of angular momentum \[mvr=mv'\frac{r}{2}\] \[v'=2v\]                 So,          \[\frac{{{k}_{1}}}{{{k}_{2}}}=\frac{\frac{1}{2}m{{v}^{2}}}{\frac{1}{2}m{{v}^{'2}}}\]                                 \[\frac{{{k}_{1}}}{{{k}_{2}}}=\frac{{{v}^{2}}}{v{{'}^{2}}}\]                                 \[=\frac{{{v}^{2}}}{{{(2v)}^{2}}}\]                                 \[\frac{{{k}_{1}}}{{{k}_{2}}}=\frac{1}{4}\]                                 \[{{k}_{1}}=\frac{1}{4}{{k}_{2}}\]                                 \[{{k}_{2}}=4{{k}_{1}}\]


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