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NEET AIPMT SOLVED PAPER MAINS 2010

  • question_answer
    The thermo emf E in volt of a certain thermo-couple is found to vary with temperature difference \[\theta \] in\[{}^\circ C\]  between the two junctions according to the relation \[E=30\,\theta -\frac{{{\theta }^{2}}}{15}\] The neutral temperature for the thermo-couple will be                                        

    A)  \[{{450}^{o}}C\]

    B)  \[400{}^\circ C\]

    C)  \[225{}^\circ C\]

    D)  \[30{}^\circ C\]

    Correct Answer: C

    Solution :

    Given, \[E=30\theta -\frac{{{\theta }^{2}}}{15}\] At neutral temperature \[\frac{dE}{d\theta }=0\]                 \[\therefore \]  \[30-\frac{2\theta }{15}=0\]                                 \[\theta ={{225}^{o}}C\]


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