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NEET AIPMT SOLVED PAPER 2003

  • question_answer
                    The value of Planck's constant is \[6.63\times {{10}^{34}}Js\]. The velocity of light is \[3.0\times {{10}^{8}}m{{s}^{-1}}\]. Which value is closest to the wavelength in nanometers of a quantum of light with frequency of \[8\times {{10}^{15}}{{s}^{-1}}\]?               

    A)                 \[4\times {{10}^{1}}\]         

    B)                 \[3\times {{10}^{7}}\]         

    C)                 \[2\times {{10}^{-25}}\]     

    D)                 \[5\times {{10}^{-18}}\]

    Correct Answer: A

    Solution :

                    \[\therefore \]Frequency = \[\frac{c}{\lambda }=\frac{3\times {{10}^{8}}m\,{{s}^{-1}}}{8\times {{10}^{15}}\,{{s}^{-1}}}\]                 \[=0.375\times {{10}^{-7}}\,m\]                 \[=3.75\times {{10}^{1}}\,nm\,\approx \,4\times {{10}^{1}}\,nm\]


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