A) \[[Cr{{(CO)}_{6}}]\]
B) \[[Fe{{(CO)}_{5}}]\]
C) \[{{[Fe{{(CN)}_{6}}]}^{4-}}\]
D) \[{{[Cr{{(N{{H}_{3}})}_{6}}]}^{3+}}\]
Correct Answer: D
Solution :
Atoms, ions or molecules having unpaired electrons are paramagnetic. In \[[Cr(N{{H}_{3}})_{6}^{3+}\]Cr is present as Cr (III) or \[C{{r}^{3+}}\] So electronic configuration is \[\underset{Ground\,state}{\mathop{_{24}Cr+}}\,1{{s}^{2}},\,2{{s}^{2}}\,2{{p}^{6}},\,3{{s}^{2}}\,3{{p}^{6}}\,3{{d}^{5}},\,4{{s}^{1}}\] \[C{{r}^{3+}}=1{{s}^{2}},\,2{{s}^{2}}2{{p}^{6}},\,3{{s}^{2}}3{{p}^{6}}3{{d}^{3}}\]You need to login to perform this action.
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