NEET AIPMT SOLVED PAPER 2001

  • question_answer
                    Nitrogen forms \[{{N}_{2}}\], but phosphorus when form \[{{P}_{2}}\] readily converted into \[{{P}_{4}},\] reason is:            

    A)                 triple bond present between phosphorus atom

    B)                 \[{{P}_{\pi }}-{{P}_{\pi }}\] bonding is weak

    C)                 \[{{P}_{\pi }}-{{P}_{\pi }}\] bonding is strong      

    D)                 multiple bond form easily

    Correct Answer: B

    Solution :

                    Nitrogen form \[{{N}_{2}}\] (i. e., N\[\equiv \]N) but phosphorus form \[{{P}_{2}}\], it is at a time convert in \[{{P}_{4}}\], because in \[{{P}_{2}}\], \[{{P}_{\pi }}-{{P}_{\pi }}\] bonding is present which is a weaker bonding due to larger size.


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