A) \[1.568\,\times {{10}^{4}}\]
B) \[1.568\,\times {{10}^{3}}\]
C) 15.68
D) \[2.168\,\times {{10}^{4}}\]
Correct Answer: A
Solution :
Suppose the mol. wt. of enzyme = x 0.5% by weight means in 100 g of enzyme wt. of Se = 0.5g \[\therefore \] In x g of enzyme wt. of Se = \[\frac{0.5}{100}\times x\] Hence, \[78.4=\frac{0.5\,\times x}{100}\] \[\therefore \] \[x=15680=1.568\times {{10}^{4}}\]
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