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NEET AIPMT SOLVED PAPER 2001

  • question_answer
                       A human body required the 0.01 M activity of radioactive substance after 24 hour. Half-life of radioactive is 6 hour. Then injection of maximum activity of radioactive substance that can be injected:               

    A)                                                                                                                                                            0.08       

    B)                 0.04       

    C)                 0.16                       

    D)                 0.32

    Correct Answer: C

    Solution :

                    Remaining activity = 0.01 M after 24 hrs Remaining activity                 = Initial activity \[\times {{\left( \frac{1}{2} \right)}^{n}}\]                 Used half life time (n)                 \[=\frac{Total\,time}{{{T}_{1/2}}}=\frac{24}{6}=4\]                 So 0.01 = Initial activity \[\times {{\left( \frac{1}{2} \right)}^{4}}\]                 Initial activity = \[0.0116=0.16\]


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