NEET AIPMT SOLVED PAPER 2001

  • question_answer
                    A particle of mass M is revolving along a circle of radius R and another particle of mass m is revolving in a circle of radius r. If time periods of both particles are same, then the ratio of their angular velocities is:

    A)                                                                                                                                                                                            1             

    B)                 \[\frac{R}{r}\]                   

    C)                 \[\frac{r}{R}\]                   

    D)                 \[\sqrt{\frac{R}{r}}\]

    Correct Answer: A

    Solution :

                              Angular velocity of particle is                 \[\omega =\frac{2\pi }{T}\,or\,\omega \propto \,\frac{1}{T}\]                 It simply implies that  does not depend on mass of the body and radius of the circle.                         \[\therefore \frac{{{\omega }_{1}}}{{{\omega }_{2}}}=\frac{{{T}_{2}}}{{{T}_{1}}}\]                 but time period is given same, i.e., \[{{T}_{1}}={{T}_{2}}\]                 Hence,  \[\frac{{{\omega }_{1}}}{{{\omega }_{2}}}=\frac{1}{1}\]


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