A) \[_{2}H{{e}^{4}}\]
B) \[_{5}{{B}^{10}}\]
C) \[_{5}{{B}^{9}}\]
D) \[_{4}B{{e}^{11}}\]
Correct Answer: B
Solution :
Key Idea: In a nuclear reaction conservation of both the charge number and mass number must hold. The given nuclear reaction can be written as \[_{Z}{{X}^{A}}+{{\,}_{0}}{{n}^{1}}\,\to \,{{\,}_{3}}L{{i}^{7}}+{{\,}_{2}}H{{e}^{4}}\] Conservation of mass number gives, A + 1 = 7 + 4 \[\Rightarrow A=10\] Conservation of charge number gives, Z + 0 = 2 + 3 \[\Rightarrow \] Z = 5 Hence, Z = 5, A = 10 correspond to Boron \[{{(}_{5}}{{B}^{10}})\].
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