A) \[\frac{n}{2}\]
B) 2n
C) 4n
D) n
Correct Answer: C
Solution :
Intensity of Sight source is given by \[I\,\propto \,\,\frac{1}{{{d}^{2}}}\] where d Is the distance of tight source from the cell. or \[\frac{{{I}_{1}}}{{{I}_{2}}}={{\left( \frac{{{d}_{2}}}{{{d}_{1}}} \right)}^{2}}={{\left( \frac{1}{2} \right)}^{2}}=\frac{1}{4}\] \[or{{I}_{2}}=4{{I}_{1}}\] As number of photoelectrons emitted is directly proportional to intensity, so number of photoelectrons emitted will become 4 times, i.e., 4n.
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