A) 0.3 N
B) 3 N
C) 30 N
D) 300 N
Correct Answer: C
Solution :
Key Idea: The force imparted (or impulse) by the ball to the hands of the player is equal to the rate of change of linear momentum. Force imparted = Rate of change of momentum \[orF=\frac{\Delta p}{\Delta t}\] \[orF=\frac{{{p}_{1}}-{{p}_{2}}}{\Delta t}\] \[orF=\frac{m({{v}_{1}}-{{v}_{2}})}{\Delta t}\] Here, m = 150 g = 0.150 kg, v1 = 20 m/s, v2 = 0 \[\Delta t=0.1\,\,s\] \[\therefore F=\frac{0.150\times (20-0)}{0.1}=30\,N\]
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