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NEET AIPMT SOLVED PAPER 1999

  • question_answer
                    How many gram of dibasic acid (mol. wt. 200) should be present in 100 mL of the aqueous solution to give 0.1 N?         

    A)                                                                                                                                                                         1 g                            

    B)              2 g                            

    C)              10 g          

    D)              20 g

    Correct Answer: A

    Solution :

                    Equivalent wt. of dibasic acid = \[\frac{Mol\,.wt.}{2}\]                                                                    \[=\frac{200}{2}=100\]                 Strength = 0.1 N, m = ?, V = 100 mL                 then,                 \[m=\frac{E\,V\,N}{1000}=\frac{100\times 100\times 0.1}{1000}=1\,g\]


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