A) 3.3 \[\overset{\text{o}}{\mathop{\text{A}}}\,\]
B) 3.9 \[\overset{\text{o}}{\mathop{\text{A}}}\,\]
C) 4.3 \[\overset{\text{o}}{\mathop{\text{A}}}\,\]
D) 4.8 \[\overset{\text{o}}{\mathop{\text{A}}}\,\]
Correct Answer: C
Solution :
The distance between any two nearest neighbours (atoms) in body centered lattice is \[\frac{\sqrt{3}}{2}a\], where \[a\] is lattice parameter. We have given \[\frac{\sqrt{3}}{2}a=3.7\] \[\therefore \] \[a=\frac{3.7\times 2}{\sqrt{3}}=\frac{3.7\times 2}{1.773}=4.3\,\overset{\text{o}}{\mathop{\text{A}}}\,\]
You need to login to perform this action.
You will be redirected in
3 sec
