A) 1.6 A
B) 2 A
C) 0.32 A
D) 3.2 A
Correct Answer: B
Solution :
In the given circuit resistances \[{{R}_{B}}\] and \[{{R}_{C}}\] are in series order, so their effective resistance, \[R'={{R}_{B}}+{{R}_{C}}=6+6=12\Omega \] Now \[{{R}_{A}}\] and R' are in parallel order, hence net resistance of the circuit \[R=\frac{R'\times {{R}_{A}}}{R+{{R}_{A}}}=\frac{12\times 3}{12+3}=\frac{36}{15}\Omega \] The current flowing in the circuit \[I=\frac{V}{R}=4.8\,\times \frac{15}{36}=2A\]
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