A) law of definite proportions
B) law of reciprocal proportions
C) law of multiple proportions
D) law of conservation of mass
Correct Answer: C
Solution :
If \[\text{C}=\text{ 42}.\text{9}%\]then \[O=\text{1}00-\text{42}.\text{9}=\text{57}.\text{1}%\] Let 100g of the compound is taken, then 1 g oxygen combines with \[=\frac{42.9}{57.1}=0.75g\] carbon. In the second compound, \[O=\text{1}00-\text{27}.\text{3 n }=\]72.7% 1g oxygen combines with\[=\frac{273}{72.7}=0.375g\]of carbon Ratio of carbon in two compounds combining with fixed weight of oxygen \[=0.\text{75}:0.\text{375}=\text{2}:\text{1}\] Hence, it supports law of multiple proportion.
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