question_answer

One mole of magnesium in the vapour state absorbed \[\frac{{{R}_{1}}}{{{R}_{2}}}\] energy. If the first and second ionisation energies of Mg are 750 and \[\left| \frac{dL}{dt} \right|\] respectively, the final composition of the mixture is

A) \[2\,\,m\,\,{{l}^{3}}{{\omega }^{2}}\sin \theta .\cos \theta \]

B) \[\,m\,\,{{l}^{2}}{{\omega }^{2}}\sin 2\theta \]

C) \[\,m\,\,{{l}^{2}}\sin 2\theta \]

D) \[\,{{m}^{1/2}}\,\,{{l}^{1/2}}\,\omega \,\,\sin \theta .\cos \theta \]