A) \[\text{A}=\text{1}0\text{m},\text{L}=\text{2m}\,\,\text{and}\,\,\text{d}=\text{3}0{}^\circ .\]
B) \[{{\mu }_{s}}=5,{{\mu }_{x}}=0.4,g=10m/{{s}^{2}}\]
C) \[\text{1 m}/{{\text{s}}^{\text{2}}}\]
D) \[\text{2 m}/{{\text{s}}^{\text{2}}}\]
Correct Answer: C
Solution :
Order of \[p{{K}_{b}}\] values \[{{C}_{6}}{{H}_{5}}N>{{C}_{6}}{{H}_{5}}NHC{{H}_{3}}>{{({{C}_{2}}{{H}_{5}})}_{2}}NH>{{C}_{2}}{{H}_{5}}N{{H}_{2}}\]This is simply because \[+I-\]effect of \[{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{5}}}\]group increases the basicity of amine while \[-I-\]effect of \[{{C}_{6}}{{H}_{5}}\] group decreases the basicity of amine.
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