A) \[C{{H}_{3}}CHO+N{{H}_{2}}.N{{H}_{2}}\to A\]
B) \[\xrightarrow{B}C{{H}_{3}}C{{H}_{3}}+{{N}_{2}}\]
C) \[C{{H}_{3}}CH=NN{{H}_{2}}\,and\,{{C}_{2}}{{H}_{5}}ONa\]
D) \[\text{C}{{\text{H}}_{\text{3}}}\text{C}{{\text{H}}_{\text{2}}}\text{N}{{\text{H}}_{\text{2}}}\text{ and}\,{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{5}}}\text{ONa}\]
Correct Answer: B
Solution :
\[~\underset{A}{\mathop{\text{2Na}}}\,-\text{2}{{\text{H}}_{\text{2}}}\text{O}\to \underset{B}{\mathop{{{\text{H}}_{\text{2}}}}}\,+\underset{C}{\mathop{\text{2NaOH}}}\,\] \[\underset{D}{\mathop{Zn}}\,+\underset{C}{\mathop{2NaOH}}\,\xrightarrow{\Delta }N{{a}_{2}}Zn{{O}_{2}}+\underset{B}{\mathop{{{H}_{2}}}}\,\] \[\underset{D}{\mathop{Zn}}\,+{{H}_{2}}S{{O}_{4}}\xrightarrow{\Delta }ZnS{{O}_{4}}+\underset{B}{\mathop{{{H}_{2}}}}\,\] With Bunsen burner, Na gives golden yellow flame, K gives pink violet flame whereas Ca gives brick red colour.
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