A)
B)
C)
D)
Correct Answer: A
Solution :
According to Charle's law \[\cos \theta =\frac{2R}{\sqrt{{{R}^{2}}+\omega {{L}^{2}}}}\] (at constant p) i.e. \[\frac{4}{5}r\] If \[h/4\] \[\lambda /4\] \[\left( \text{kJ mo}{{\text{l}}^{\text{-1}}} \right)\]
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