A) 40m/s
B) 55.5m/s
C) 26.1 m/s
D) 9.6 m/s
Correct Answer: C
Solution :
Let the ball hit water in t s. For first ball \[\Rightarrow \] \[\varepsilon =BA\omega \cos (\theta -\pi /2)\] \[{{f}_{0}}=\frac{1}{2\pi }\sqrt{\frac{1}{LC}-\frac{{{R}^{2}}}{{{L}^{2}}}}\] For second ball, \[\Rightarrow \] \[{{f}_{0}}=\frac{1}{2\pi }\sqrt{\frac{1}{LC}-\frac{{{R}^{2}}}{{{L}^{2}}}}\] \[=\frac{1}{2\times 3.14}\sqrt{\frac{1}{250\times {{10}^{-6}}\times 0.16\times 10-3}-\frac{20\times 20}{{{(0.16\times {{10}^{-3}})}^{2}}}}\]
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