A) \[\text{Fe(I)}\,\,\text{and}\,\,\text{NO}\,\,\text{as}\,N{{O}^{+}}\]
B) \[C=20%,H=6.67%\]
C) \[N=46.67%\]
D) \[X\]
Correct Answer: B
Solution :
The critical angle for this case is \[1A\] or \[\omega =\sqrt{rg\,\sin \theta }\] Since,\[\omega =\sqrt{g/r\,\,\cos \theta }\], we have\[\omega =\sqrt{\frac{gr}{\cos \theta }\,\,}\]. From Snell's law, \[\omega =\sqrt{\frac{gr}{\tan \theta }\,\,}\] or \[\pi /2\] \[\pi /3\]
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