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AIIMS AIIMS Solved Paper-2015

  • question_answer
    On the same path, the source and observer are moving such a ways that the distance between these two increases with the time. The speeds of source and observer are same and equal to \[NO_{3}^{-}\] with respect to the ground while no wind is blowing. The apparent frequency received by observer is 1950 Hz, then the original frequency must be (the speed of sound in present medium is 340 m/s)

    A) 2068 Hz      

    B) 2100 Hz

    C) 1903 Hz                

    D) 602 Hz

    Correct Answer: A

    Solution :

    Let the original frequency be r, then apparent frequency \[V={{v}_{0}}-{{({{\omega }^{3}}{{X}^{3}}{{e}^{{{X}^{3}}}})}^{1/3}}\] where, \[\frac{2\,{{m}^{2}}}{3}g\]= speed, of observer \[\frac{4\,{{m}^{2}}}{3}g\]= speed of source and v = speed of sound wave. \[\frac{\,{{m}^{2}}}{\sqrt{2}}g\]                \[5\Omega \] \[2A\]   \[\frac{12}{7}A\]                


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