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AIIMS AIIMS Solved Paper-2015

  • question_answer
    The force on a particle as the function of displacement x (in x-direction) is given by \[\text{A=III,B=II}\] The work done corresponding to displacement of particle from\[x=0\]to\[x=2\] unit is

    A) 25J                                         

    B) 29J

    C) 21J                                         

    D) 18J

    Correct Answer: C

    Solution :

    To determine the overall work done, we calculate the small work done for the displacement\[dx\]as \[{{O}_{2}}\] \[{{O}_{1}}\]                      \[{{O}_{2}}\] Now, the total work done for the displacemer from x = 0 to x = 2 unit \[\left( \text{given},\text{hc=124}0\text{ eV}-\text{nm},\text{e}=\text{1}.\text{6}\times \text{1}{{0}^{-\text{19}}}\text{ C} \right)\] \[5\mu A\]


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