AIIMS AIIMS Solved Paper-2015

  • question_answer
    A uniform sphere of mass 500 g rolls without slipping on a plane surface so that its centre moves at a speed of 0.02 m/s. The total kinetic energy of rolling sphere would be (in J)

    A) \[\text{III}\]                      

    B) \[\text{IV}\]

    C) \[\text{A=I,B=IV}\]        

    D) \[\text{A=IV,B=I}\]

    Correct Answer: A

    Solution :

    Let the velocity of centre of sphere be v. The angular speed of the sphere about its centre is given by \[\left[ \text{ML}{{\text{Q}}^{-\text{2}}} \right]\] where, r = radius of sphere. The total kinetic energy =translational kinetic energy 4- rotational kinetic energy \[[L\,\,{{T}^{-1}}{{Q}^{-1}}]\] \[[M{{L}^{2}}\,\,{{T}^{-1}}{{Q}^{-2}}]\] \[\left[ \text{LT}{{\text{Q}}^{-\text{1}}} \right]\] \[{{O}_{1}}\]


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