AIIMS AIIMS Solved Paper-2015

  • question_answer
    For Bragg's diffraction by a crystal to occur, then the X-ray of wavelength X and interatomic distance d must be

    A) \[\cos \theta =\frac{2R}{\sqrt{{{R}^{2}}+\omega {{L}^{2}}}}\]

    B) \[\frac{4}{5}r\]

    C) \[h/4\]

    D) \[\lambda /4\]

    Correct Answer: C

    Solution :

    For Bragg's diffraction, \[\frac{3{{\mu }_{0}}i}{7R}\] \[\text{P }+\text{ }\overline{\text{P}}\text{Q}\]


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