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AIIMS AIIMS Solved Paper-2015

  • question_answer
    Two spherical nuclei have mass numbers 2l6 and 64 with their radii \[V=\sqrt{v_{0}^{2}+{{\omega }^{2}}{{X}^{2}}}\] and \[V=\sqrt{v_{0}^{2}-{{\omega }^{2}}{{X}^{2}}}\]respectively The ratio, \[V=\sqrt[3]{v_{0}^{3}+{{\omega }^{3}}{{X}^{3}}}\] is equal to

    A) \[3:2\]   

    B) \[1:3\]        

    C) \[1:2\]                                  

    D) \[2:3\]

    Correct Answer: A

    Solution :

    Radius of nuclei having mass number A is determined as \[\text{IIIIII}\]   (where, \[{{S}_{2}}(g)+2{{O}_{2}}(g)\to 2S{{O}_{2}}(g);\Delta G=-544KJ\] = constant) \[2Zn(s)+{{S}_{2}}(g)\to 2ZnS(s);\Delta G=-293KJ\] This implies,                 \[2Zn(s)+{{O}_{2}}(g)\to 2ZnS(s);\Delta G=-480KJ\]                 \[\Delta G\]        \[2Zn(s)+3{{O}_{2}}(g)\to 2ZnO(g)+2S{{O}_{2}}(g)\]                                


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