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AIIMS AIIMS Solved Paper-2014

  • question_answer
    In a basic buffer, 0.0025 mole of \[N{{H}_{4}}Cl\] and 0.15 mole of \[N{{H}_{4}}OH\] are present. The pH of the solution will be (\[(p{{K}_{a}})=4.74\].

    A) 11.04  

    B) 10.24   

    C) 6.62                       

    D) 5.48

    Correct Answer: A

    Solution :

                    From Henderson's equation, \[pOH=p{{K}_{b}}+\log \frac{[salt]}{[base]}\] \[=4.74+\log \frac{0.0025/V}{0.15/V}\] \[=4.74+\log \frac{1}{60}\] \[=4.74-1.78=2.96\] \[pH=14-2.96\] \[=11.04\]                                


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