A) \[{{H}_{2}}(g)+B{{r}_{2}}(g)\to 2HBr(g)\]
B) \[C(s)+2{{H}_{2}}O(g)\to 2{{H}_{2}}(g)+C{{O}_{2}}(g)\]
C) \[PC{{l}_{5}}(g)\to PC{{l}_{3}}(g)+C{{l}_{2}}(g)\]
D) \[2CO(g)+{{O}_{2}}(g)\to 2C{{O}_{2}}(g)\]
Correct Answer: A
Solution :
\[\Delta H=\Delta E+\rho \Delta V\] \[\Delta H=\Delta E+\Delta nRT\] If \[\Delta n=0\] for reactions which is carried out in an open container, therefore \[\Delta H=\Delta E\] So, for the reaction (a) \[\Delta n=2-2=0\] Hence, for the reaction \[\Delta H=\Delta E\]
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