A) \[C{{H}_{3}}CN\xrightarrow[HCl]{Snc{{l}_{2}}}C{{H}_{3}}CH=NH\] \[\xrightarrow{{{H}_{3}}{{O}^{+}}}C{{H}_{3}}CHO\]
B) \[C{{H}_{3}}COCl+{{H}_{2}}\xrightarrow[BaS{{O}_{4}}]{pd}C{{H}_{3}}CHO+HCl\]
C) \[C{{H}_{2}}=C{{H}_{2}}+{{H}_{2}}O\xrightarrow{p{{b}^{2+}}}C{{H}_{3}}CHO\]
D) All of the above
Correct Answer: C
Solution :
It is Wacker process. \[C{{H}_{2}}=C{{H}_{2}}+pbC{{l}_{2}}+{{H}_{2}}O\xrightarrow{{}}C{{H}_{3}}CHO\] \[+pb+2HCl\] \[pb+2CuC{{l}_{2}}\xrightarrow{{}}PbC{{l}_{2}}+2CuCl\] \[2CuCl+2HCl+\frac{1}{2}{{O}_{2}}\xrightarrow{{}}2CuC{{l}_{2}}+{{H}_{2}}O\] \[C{{H}_{2}}=C{{H}_{2}}+\frac{1}{2}{{O}_{2}}\xrightarrow{{}}C{{H}_{3}}CHO\]
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