A) heating sodium ethoxide with ethyl bromide
B) passing ethanol over heated alumina
C) treating ethyl alcohol with excess of cone. \[{{H}_{2}}S{{O}_{4}}\] at 430 - 440 K
D) heating ethanol with dry \[A{{g}_{2}}O\]
Correct Answer: A
Solution :
\[C{{H}_{3}}C{{H}_{2}}ONa+C{{H}_{3}}C{{H}_{2}}Br\xrightarrow[Synthesis]{Williamson's}\] \[\underset{Ethoxy\,ethane}{\mathop{C{{H}_{3}}C{{H}_{2}}OC{{H}_{2}}C{{H}_{3}}}}\,+NaBr\]
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