A) \[0.1MKN{{O}_{3}}\]
B) \[0.1MN{{a}_{3}}P{{O}_{4}}\]
C) \[0.1M\,BaC{{l}_{2}}\]
D) \[0.1M{{K}_{2}}S{{O}_{4}}\]
Correct Answer: B
Solution :
\[\Delta {{T}_{b}}=i{{k}_{b}}m\] Maximum elevation will be there where value of \[i\] is maximum follows. Value of \[i\] for the molecules is as \[KN{{O}_{3}}=2,N{{a}_{3}}P{{O}_{4}}=4BaC{{l}_{2}}=3,{{K}_{2}}S{{O}_{4}}=3\] Thus, \[N{{a}_{3}}P{{O}_{4}}\] has the highest boiling point.
You need to login to perform this action.
You will be redirected in
3 sec
