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AIIMS AIIMS Solved Paper-2014

  • question_answer
    The thermo emf E (in volts) of a certain thermocouple is found to vary with Q (in C) according to equation (\[E=20Q-\frac{{{Q}^{2}}}{20}\], where\[Q\]is temperature of the hot function, the cold function being kept at\[0{}^\circ C\]. Then, the neutral temperature of the thermocouple is

    A) \[300{}^\circ C\]              

    B) \[400{}^\circ C\]

    C) \[100{}^\circ C\]              

    D) \[200{}^\circ C\]

    Correct Answer: D

    Solution :

                    \[E=20Q-\frac{{{Q}^{2}}}{20}\] \[Q={{Q}_{n}},\frac{dE}{dQ}=0\] \[\frac{dE}{d\theta }=20-\frac{2{{Q}_{n}}}{20}=0\] \[{{Q}_{n}}={{200}^{\circ }}C\]


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