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AIIMS AIIMS Solved Paper-2014

  • question_answer
    A magnet is cut in three equal parts by cutting it perpendicular to its length. The time period of original magnet is \[{{T}_{0}}\] in a uniform magnetic field B. Then, the time period of each part in the same magnetic field is

    A) \[\frac{{{T}_{0}}}{2}\]                    

    B) \[\frac{{{T}_{0}}}{3}\]

    C) \[\frac{{{T}_{0}}}{4}\]                                    

    D) None of these

    Correct Answer: B

    Solution :

                    In the case of vertical cutting \[{{T}_{1}}=\frac{\text{Original time period}}{n}\] \[{{T}_{1}}=\frac{{{T}_{0}}}{3}\]


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