A) \[{{v}_{0}}>{{v}_{H}}\]
B) \[4{{v}_{0}}=9{{v}_{H}}\]
C) \[2{{v}_{0}}=3{{v}_{H}}\]
D) \[9{{v}_{0}}=134{{v}_{H}}\]
Correct Answer: C
Solution :
\[\frac{{{v}_{H}}}{{{v}_{0}}}=\sqrt{\frac{{{T}_{H}}}{{{T}_{0}}}}\] \[=\sqrt{\frac{300}{675}}\] \[=\sqrt{\frac{4}{9}}\] \[\frac{v+1}{{{v}_{0}}}=\frac{2}{3}\] \[3{{v}_{H}}=2{{v}_{0}}\]
You need to login to perform this action.
You will be redirected in
3 sec
