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AIIMS AIIMS Solved Paper-2014

  • question_answer
    A block has been placed on an inclined plane with the slope angle \[\theta ,\]block slide down the plane at constant speed. The coefficient of kinetic friction is equal to

    A) \[\sin \theta \]                 

    B) \[\cos \theta \]

    C) \[g\]                                     

    D) \[\tan \theta \]

    Correct Answer: D

    Solution :

                    When a block slides down the plane with a constant speed, then the inclination of the plane is equal to angle of repose \[(\theta )\]. Coefficient of friction = the angle of repose \[=\text{tan}\theta \]


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