A) 0.16
B) 0.36
C) 0.48
D) 0.24
Correct Answer: C
Solution :
According to Hardy-Weinberg equation, \[{{\text{P}}^{\text{2}}}+\text{2PQ}+{{Q}^{\text{2}}}=\text{1}\] Where, P = Dominant allele frequency \[Q\]= Recessive allele frequency \[{{\text{P}}^{\text{2}}}\]= Homozygous dominant genotype 2PQ = Heterozygous genotype \[{{Q}^{\text{2}}}\] = Homozygous recessive genotype Here, P=0.6 and \[Q\]=0.4 Therefore, \[\text{2PQ }=\text{2}\times 0.\text{6}\times 0.\text{4}\] =0.48
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