A) \[\sqrt{2}:1\]
B) \[3:1\]
C) \[2:1\]
D) \[1:2\]
Correct Answer: C
Solution :
\[V=\frac{Dis\tan ce}{Time\,taken}\] As shown in given figure \[\frac{{{v}_{1}}}{{{v}_{0}}}=\frac{\frac{{{s}_{0}}}{{{t}_{1}}}}{\frac{{{s}_{0}}}{{{t}_{2}}}}\] \[=\frac{{{s}_{0}}}{{{t}_{1}}}\times \frac{{{t}_{2}}}{{{s}_{0}}}\] \[\frac{{{v}_{1}}}{{{v}_{2}}}=\frac{4}{2}=\frac{2}{1}\] Therefore, the ratio of speeds is \[{{v}_{1}}:{{v}_{2}}=2:1\]
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