AIIMS AIIMS Solved Paper-2014

  • question_answer
    Considering normal incidence of ray, the equivalent refractive index of combination of two slabs shown in figure is
    \[\mu =4/3\]
    \[\mu =3/2\]

    A) 1.8                                         

    B) 1.43

    C) 2                                             

    D) None of the above

    Correct Answer: B

    Solution :

                     \[\mu =\frac{\sum {{t}_{i}}}{\sum \frac{{{t}_{i}}}{{{\mu }_{i}}}}\] \[\mu =\frac{{{t}_{1}}+{{t}_{2}}}{\frac{{{t}_{1}}}{{{\mu }_{i}}}+\frac{{{t}_{2}}}{{{\mu }_{2}}}}=\frac{10+15}{\frac{10}{4/3}+\frac{15}{3/2}}\] \[=\frac{25}{7.5+10}=\frac{25}{17.5}=1.43\]


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