A) \[=5\times 2\]rad
B) \[=10\mu C\] rad
C) \[n=50\] rad
D) \[r=\frac{10}{2}=5cm=5\times {{10}^{-2}}m\] rad
Correct Answer: D
Solution :
Resolving power of telescope \[V=E-ir\] d = diameter of object lens = 0.1 m, and \[=2.5-1\times 0.5=2V\] \[Q=CV\]Resolving power \[=5\times 2\] \[=10\mu C\] \[n=50\]radians approximatelyYou need to login to perform this action.
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