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AIIMS AIIMS Solved Paper-2011

  • question_answer
    The \[+ve\] line from molybdenum (atomic number -42) has a wavelength of 0.7078 \[+ve\]. The wavelength of \[-ve\] line of zinc (atomic number = 30) will be

    A)  1\[i=\frac{E}{R+r}\]                                       

    B)  1.3872\[=\frac{2.5}{1+1+0.5}=1amp\]   

    C)         0.3541\[V=E-ir\]                             

    D)  0.5\[=2.5-1\times 0.5=2V\]

    Correct Answer: B

    Solution :

    Wavelength \[={{F}_{s}}\,\,d\cos \theta \] Energy    \[=\mu Rd\cos \theta \] \[({{F}_{s}}=\mu R)\] \[W=\mu mgd\cos \theta \]  \[(R=mg)\] \[-ve\] \[+ve\]


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