AIIMS AIIMS Solved Paper-2010

  • question_answer
    The root mean square velocity of one mole of a monatomic gas having molar mass M is \[{{U}_{rms}}\]. The relation between the average kinetic energy (E) of the gas and \[{{U}_{rms}}\]is

    A) \[{{U}_{rms}}=\sqrt{\frac{3E}{2M}}\]

    B)        \[{{U}_{rms}}=\sqrt{\frac{2E}{3M}}\]

    C)                        \[{{U}_{rms}}=\sqrt{\frac{2E}{M}}\]

    D)        \[{{U}_{rms}}=\sqrt{\frac{E}{3M}}\]

    Correct Answer: C

    Solution :

    Average kinetic energy, \[E=\frac{3}{2}RT\]                                            .....(i) Root mean square velocity, \[{{U}_{rms}}=\sqrt{\frac{3RT}{M}}\] From eq. (i), \[RT=\frac{2E}{3}\] On putting the value of RT in the expression of \[{{U}_{rms}},\]we get \[{{U}_{rms}}=\sqrt{\frac{3\times 2E}{3M}}=\sqrt{\frac{2E}{M}}\]


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