A) oxygen gives colour to it
B) charge transfer when \[Mn\] gives its electron to oxygen
C) charge transfer when oxygen gives its electron to \[Mn\] making it \[Mn\left( +VI \right)\].
D) presence of unpaired electrons
Correct Answer: C
Solution :
Although in \[MnO_{4}^{-},\], the oxidation state of Mn is +7, ie, it contains no unpaired electrons, yet it is coloured. This is because oxygen gives its one electron to Mn and converts it into Mn(VI), which is coloured. Thus, the colour of \[MnO_{4}^{-},\] is due to charge transfer.
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